2x^2+xy+3y^2=0dx

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Solution for 2x^2+xy+3y^2=0dx equation:


Simplifying
2x2 + xy + 3y2 = 0dx

Reorder the terms:
xy + 2x2 + 3y2 = 0dx

Anything times zero is zero.
xy + 2x2 + 3y2 = 0dx

Solving
xy + 2x2 + 3y2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
0.5xy + x2 + 1.5y2 = 0

Move the constant term to the right:

Add '-1.5y2' to each side of the equation.
0.5xy + x2 + 1.5y2 + -1.5y2 = 0 + -1.5y2

Combine like terms: 1.5y2 + -1.5y2 = 0.0
0.5xy + x2 + 0.0 = 0 + -1.5y2
0.5xy + x2 = 0 + -1.5y2
Remove the zero:
0.5xy + x2 = -1.5y2

The x term is xy.  Take half its coefficient (0.5y).
Square it (0.25y2) and add it to both sides.

Add '0.25y2' to each side of the equation.
0.5xy + x2 + 0.25y2 = -1.5y2 + 0.25y2

Combine like terms: -1.5y2 + 0.25y2 = -1.25y2
0.5xy + x2 + 0.25y2 = -1.25y2

Factor a perfect square on the left side:
(x + 0.5y)(x + 0.5y) = -1.25y2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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